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3 A = Tr2 C=2rr V = Tr h tan (0) 10- 30° 45° 600 Ssın xdx=- cos x+C Sin 2. dx -=tgx +C, cosx Cos Hgxdk=-Inlcosxl+ 5- tan 2x 60 Sin x 30° dk olad -arctg a+X xp

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1 sin COS A = πr.² Пра C = 2πr tan a IN N r 3 30° 45° 45° α WW 2x 30° 2 2 x√3 a√2 60° '3 www 3 60 I si S sinxd dx cos² x tanxdx dx sin x = = cos x + C - In |cos x + C dx a² + x² a tan x + C In tan + C X In X arctan + C a dx 1 |_ *- ! - - - 1|²+ª|+c x a a² x² 2a x a C V tan (0) 10 5 HIM 3 h I Tr2h | 0/rad h ax²+bx+c = 0 X b x² +2. x + 2a b 2a x + x + V = πr + -x + 2a 2 a + b 2a 0 2 6² - 4ac 4a² √6² 4ac 2a -b ± √b² - 4ac 2a r πη2 b 2a C

3 _A = r² C = 2лr sin COS tan Meme news: The Brazilian actress Renata Sorrah came out as bisexual at the age of 76 That's her, btw 30° 45 60° ప|| || NI cria-do-118 Follow 3d ago 17277 2x 30⁰ 45° x√3 212 60% [sin xdx = = COSX+C dx tgx+C. COS X ftgoede--Injeosx+ sinx Intg+C V = 3T tan (0) 10- h 9/nd She's an icon and also very talented. We Stan. paulgadzikowski Follow 3d ago now we know what she was trying to work out r V = r²h +3x+c=0

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