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The gravity of the cluster situation by Mod Greg So, we found the cluster to contain about 89 billion gems. That's a pretty heavy gem there. Would it be enough for a signific ant gravitational pull? So how much does it weigh? Ill assume the gems kept their density and weren't compressed further by being underground. It had some open space which might be because it shrunk from its original size, but lets not go with that. First, we have to make an assumption of what sort of gems are in that behemoth. Let's just assume equal losses in the war from both Homeworld and the Rebellion. 44.4 billion gems each. Homeworld probabły had mostly sent Quartz gems, while the rebellion would be a mix of any gemstone. I'll go with Pearls, Rubies, Quartz gems, corundum and The average density for the Homeworld half would be the average quartz gem density of 2.65g/cm2 The average density for the Rebellion Half would be the average of each gem type density (I assume the rebellion to be equal parts of each gem type Pearls : 2.725 g/c ㎡ Quartz: 2.65 g/cm Rubies/Sapphires: 4.00 g/cm Corundum: 4.025 g/cm Tourmaline: 3.07 g/cm The average density for the Rebellion Half would then be 3.294 g/cm The cluster's density, according to me, is then 2.972 g/cmP with a total weight of about 10*10 kg. Is this enough for a signific ant gravitational pull? m"G/d2 with d the cluster's radius, m its weight and G a F m1*m2"G/cF <-> g constant. g 0.311 mm/s: this is 0.003% of earth's surface acceleration. So, Steven would only be 0.003% heavier because of the cluster. Not really significant. So what if it was condensed? Well, the cluster's density would then be 5.6 g/cm at the most, which would give it an extra gravitational pull of 0.006%. Still not signific ant. But what about being Its embedded deep in the mantle Peri says Free-tall acceleration of Earth 12 nner Outer Lower Upper CN e Core Mantle Mantle PREM Linear density -Constant density CO 0 246 8 10 12 14 radius in 1000 km Here we see the acceleration to be about 10.5 m/s instead of 9.81. So, Steven would be 107.04% of his original weight. Not a real problem. Apart from the emotional weight of all the lost gems crying out to him for help You still win this round, Steven.

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The gravity of the cluster situation by Mod Greg So, we found the cluster to contain about 89 billion gems. That's a pretty heavy gem there. Would it be enough for a signific ant gravitational pull? So how much does it weigh? Ill assume the gems kept their density and weren't compressed further by being underground. It had some open space which might be because it shrunk from its original size, but lets not go with that. First, we have to make an assumption of what sort of gems are in that behemoth. Let's just assume equal losses in the war from both Homeworld and the Rebellion. 44.4 billion gems each. Homeworld probabły had mostly sent Quartz gems, while the rebellion would be a mix of any gemstone. I'll go with Pearls, Rubies, Quartz gems, corundum and The average density for the Homeworld half would be the average quartz gem density of 2.65g/cm2 The average density for the Rebellion Half would be the average of each gem type density (I assume the rebellion to be equal parts of each gem type Pearls : 2.725 g/c ㎡ Quartz: 2.65 g/cm Rubies/Sapphires: 4.00 g/cm Corundum: 4.025 g/cm Tourmaline: 3.07 g/cm The average density for the Rebellion Half would then be 3.294 g/cm The cluster's density, according to me, is then 2.972 g/cmP with a total weight of about 10*10 kg. Is this enough for a signific ant gravitational pull? m"G/d2 with d the cluster's radius, m its weight and G a F m1*m2"G/cF <-> g constant. g 0.311 mm/s: this is 0.003% of earth's surface acceleration. So, Steven would only be 0.003% heavier because of the cluster. Not really significant. So what if it was condensed? Well, the cluster's density would then be 5.6 g/cm at the most, which would give it an extra gravitational pull of 0.006%. Still not signific ant. But what about being Its embedded deep in the mantle Peri says Free-tall acceleration of Earth 12 nner Outer Lower Upper CN e Core Mantle Mantle PREM Linear density -Constant density CO 0 246 8 10 12 14 radius in 1000 km Here we see the acceleration to be about 10.5 m/s instead of 9.81. So, Steven would be 107.04% of his original weight. Not a real problem. Apart from the emotional weight of all the lost gems crying out to him for help You still win this round, Steven.

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